What weight is the cutting board withstands? Floor calculation in the garage how to make a wooden floor.

11-05-2012: Sergey

Thank you very much in detail and clearly, the channel suits me.

18-01-2013: Vladislav Ivanovich

Thanks for the useful articles.
Please, please, from where the figure is 34.2 in the sentence: "Schweller has a moment of resistance to a variant 34.9 cm3, in a 24.2 cm3 system"? In the assortment found only - the channel 10p wz-34.9 cm3, but I do not see 34.2 to stop. Or did I understand something correctly?

18-01-2013: Dr. Lom.

Yes, indeed, a typo is admitted to the article. For the 27.9 cm3 of the resistance number 10. Truck corrected, thanks for attentiveness.

08-09-2013: Maxim

At the very beginning, the load 25 kg / m2 is indicated, and the moment is issued as meters. The load still needs to be divided into a cargo area, otherwise - where were the square meters?

08-09-2013: Dr. Lom.

The fact is that to simplify the calculations, the load is calculated on the beams located after 1 m or on a conditional beam with a width of 1 m. Therefore, the load on 1 m ^ 2 is multiplied by 1 m and the routers are obtained. I really voiced it too late. I will make an insert before.

20-10-2013: Alexander

Good day!
House 10x10 (9.4x9.4) It is required to fill the H-14 cm overlap plate on the beams 14 through 1.6 m (beams will be in concrete) reinforcement 8 step 250x250 in two meshs. The flow showed FM 1,4 cm. Please enteem my doubts

20-10-2013: Dr. Lom.

As far as I understood, you are going to lay metal beams most likely from the diotover, and between them there will be reinforced concrete plates. So, for a plate with a length of 1.6 m, reinforcement looks quite sufficient, but whether metal beams will withstand the load - a big question.
Another thing, if there are walls in the middle of the house, which are medium support for beams. However, you wrote anything about the inner walls.

14-02-2014: Basil

Under the conditions of the problem, the pipe 60 * 60 * 3.5, and as a result we get 2AVR No. 12, how to deal with a pipe? Throw away?

14-02-2014: Dr. Lom.

In principle, if the task is to use only the specified pipe, that is, this option. Now I will finish the addition to the article (in the commentary will not fit).

25-03-2014: Andrew

Hello, tell me, 63 An equestrian corner, laid on the support after 1,5m, will withstand the standard load (400-500 kg / m)?

26-03-2014: Dr. Lom.

05-06-2014: vladimir

kind. I got confused in the article of Wood Overlapping F Distributed 400 * 4m. And here the load is 6.5 * 400 cm. And why when the distance between the beams do the Menishi of the deflection increases

05-06-2014: Dr. Lom.

In the article about the calculation of the wooden overlap, a uniformly distributed load is considered. Here, when determining the deflection of the board, a concentrated load from the wheel is considered. There are both uniformly distributed and focused load on the beam, so
When determining the beam deflection to simplify the calculations, the concentrated load is reduced to uniformly distributed (approximately approximately). The basic principles of bringing the concentrated load to distributed are given in a separate article.
With a decrease in the distance between the beams, the deflection as boards and the beams will decrease. The article presents an example of determining the deflection of the boards at a distance between the beams 1 m and 0.8 m. When determining the deflection of the board, the span decreases, and when determining the beam deflection, the load on the beam decreases.

Yes, really the modulus of the elasticity of wood is about 1000 kg / mm ^ 2. Corrected, thanks for attentiveness.

20-08-2014: Alexei

Good evening doctor scrap
I ask for help on filling the floor in the garage on the shed and the rammed sand with a thickness of 200mm. I plan to pour B15 with a thickness of 150mm 5.5 m * 9.5 m under two passenger cars. Interested in the reinforcement scheme there is a 6mm A3 fittings.

21-08-2014: Dr. Lom.

In your case, on one side, the valve as it should not be needed (if everything is compacted as follows), and on the other hand, it is desirable to make existing fittings as the bottom and the top reinforcing plate with a cell with a cell of about 150 mm (the stove on the elastic base with several concentrated loads and other surprises). Moreover, for the upper reinforcement, 15 mm of the protective layer is sufficient, and for the lower reinforcement, the norm requires at least 60 mm of the protective layer when laying directly to the ground. Therefore, it is easier to first make concrete preparation with a thickness of about 5 cm, and then on it to make a plate 10 cm with reinforcement.

21-08-2014: Alexei

That is, if I understand correctly it will be good to make top and bottom reinforcement with a protective layer of 20mm and there and there, right?

21-08-2014: Dr. Lom.

Yes, if concrete preparation or waterproofing will be made first.

22-08-2014: Alexei

Thank you very much, waterproofing with polyethylene film 250 microns.

04-10-2014: Sergey

Dear doctor score tell me, please, whether I made a calculation for this task. And when you're upheging - you think, and not the same, seeing the same calculation, you see that even there is a stock. Just do not know how the racks will behave.
It is necessary to make a formwork to fill the slab overlap with a height of 15 cm and 7.55m x 4.25m in the lumen.
If the beams, racks and boards flooring from the board 40x150 mm, 4.25 length; 2.06 and 3.77 meters, respectively. The span between the beams is 0.9 m, the distance between the racks is 1.4 m.
Because I have a three span beam with an equal flights and a uniformly distributed load, the bending moment will be m \u003d Ql2 / 10 \u003d 400x1.42 / 10 \u003d 78.4km or 7840 kgmm. The board is used - pine 2 sorts and the moment of resistance for it w \u003d 7840 / 132.56 \u003d 59.14 cm3. And then the height of the beam will be
H \u003d? 59.14 x6 / 4 \u003d 9.42 cm We accept 10 cm (causes doubt).
We determine what load will withstand the boards. The load from concrete will approximately be
Q \u003d 0.15x2500 \u003d 375kg / m2. The load from the boards themselves with a thickness of 40 mm will be approximately
0.04x500 \u003d 20kg / m2. The overall load will be 375 + 20 \u003d 395 or for an even account of 400kg / m2.
In 1 m2 flooring 6.67 boards with a width of 15 cm. Then the load on one board 1 m long
It will be 400 / 6.67 \u003d 59.97 or 60kgm, or 6000kgsm. The required moment of resistance
Wtr \u003d 6000/100 \u003d 60cm3, then the height of the board will be? 6x60 / 15 \u003d 4.9 cm,
We accept 5 cm. Then for such a board w \u003d 15x 52/6 \u003d 375/6 \u003d 62.5 cm3.
Then the maximum bending moment 63x100 \u003d 6300kgsm, and the maximum span
2x6300 / 62.5 \u003d 12600 / 62.5 \u003d 2016 cm (something doubtful).

04-10-2014: Dr. Lom.

I will try briefly. In general, all this can be taken. Now more.

Since you have a span between the beams 0.9 m, the calculated load on the beam will be slightly smaller, however, taking into account the fact that you will navigate the formwork in concreting, the small supply will not hurt.
The height of the beam 10 cm I have no doubt, but it is according to the calculation of strength. In order not to mess with the calculation of deformations, simply take the height of the beam, equal to the height of the board.
And then you hurried a little. The load on one board of 15 cm wide can indeed be taken by 60 kg / m (and not 60 kgm), then, even if the board on 2 beams will be laid on one or several sites (such a board will be a single-span beam), then the maximum bending moment For such a short board, there will be m \u003d 60x0.9 ^ 2/8 \u003d 6.075 kgm or 607.5 kgm. Accordingly, the WTR \u003d 607.5 / 100 \u003d 6.075 cm ^ 3, and the WDC \u003d 15x4 ^ 2/6 \u003d 40 cm ^ 3, i.e. You have more than decent stock.
I advise you to see the article "Calculation of the Wooden Outlap", there all these features are considered in detail in detail, and there is also a separate article "An example of calculating a wooden rack, compression troops on the stability of a wooden rack. Here I will only say that the load on the racks is the support reactions for the three-gun beam.

06-10-2014: Sergey

Recalculated according to the article "Calculation of the Wooden Overlap" it turns out that at q \u003d 400kg / m ^ 2 and the length of the span 0.9 m, the bending moment (400x0.9 ^ 2) / 8 \u003d 4050kgsm, the moment of resistance is 4050/130 \u003d 31.15 cm ^ 3 And then the height of the beam with a width of 4 cm will be 6.84 cm. If I understand everything correctly, in principle you can increase the distance between the beams, although it will not lead it to a big savings, and in such situations it seems to me better than it Good luck.
Now on racks. Stand load \u003d 1,1Ql \u003d 1.1x400x1.4 \u003d 616 kg. With the width of the rack 4 cm, the inertia radius will be IY \u003d (IY / F) ^ 1/2 \u003d (B ^ 2/12) ^ 1/2 \u003d (4 ^ 2/12) ^ 1/2 \u003d 1.15 cm. Rack length 206cm , then the flexibility of the rack? \u003d Lo / IY \u003d 206 / 1.15 \u003d 179,13. As? \u003e 70, then? \u003d A /? 2 \u003d 3000/179.3 ^ 2 \u003d 0.094. The area of \u200b\u200bthe selected section f \u003d 4x15 \u003d 60 cm2. Now they determine whether the selected section 616 / (0.094x60) \u003d 109.22<130 кг/см2 - т.е. стоек размером 206х15х4 см вполне достаточно.Вот только с таблицей предельных значений гибкости непонятно. Мне думается, что для моей конструкции больше подходт определение "Основные элементы", для которых предельная гибкость 150 у меня же получилась 179, а по сечению вроде бы нормально. Как здесь быть и верны ли мои расчеты.

06-10-2014: Dr. Lom.

In general, everything is true, and for the racks flexibility is really vilateral, it is better to make a rack of two shotguns, then flexibility will decrease by 2 times.

07-10-2014: Dmitriy

Doctor scrap, tell me in such a question.
We are building a basement in the garage, the perimeter of the basement is posted from the FBS, the size of 4.3 * 2.3, then we plan, flood the ceiling of the basement of the Boton. At the moment, I put on the FBS 4 of the 10-ki 2-cm increments in 90 cm increments, the board was laid between the twitter, the reinforcement of the 12th reinforcement, all this will be filled with concrete (2m3) about 15 cm. Whether the 2-way The slab after grappling itself will already take part of the load. Next, the plate will be filled with a layer of clay 1.8 meters.

08-10-2014: Dr. Lom.

If a channel is about 2.3 m long, then it is quite enough for formwork, and then everything will depend on how the reinforcement is laid. If the armature is also about 2.3 m and laid along the channels, then such a stove after a durability will really have a certain carrying capacity. If the reinforcement is short, about 0.9 m long, then such a stove will still pass the load on the channel and such a chaserler should be calculated on the load from the overlying soil.

08-10-2014: Sergey

Tell me, and if I replace the beams and racks on the pipe, and make a beam two span, then whether my calculations are correct in this case?
Tube d \u003d 57, d \u003d 50; Span 2.1 M.
Cross section area F \u003d 5.88 cm2
The moment of inertia I \u003d 21.44 cm3
The moment of resistance wz \u003d Wy \u003d 7.42 cm3

Maximum bending moment
Mmax \u003d (q x l2) / 8 \u003d 400x2,12 / 8 \u003d 220.5kgm or 22050 kgf
Required torque:
Wtreb \u003d 22050/2100 \u003d 10,5cm3
Support reaction B \u003d 10Ql / 8 \u003d (10 * 400 * 2,1) / 8 \u003d 1050
IY \u003d (IY / F) inertia radius? \u003d (21,44 / 5.88) 1,2 \u003d 1.9 cm
Stand length 206cm, then rack flexibility? \u003d Lo / IY \u003d 206 / 1.9 \u003d 108.42
Coefficient of longitudinal bending? \u003d 0.520.
Estimated steel resistance. Ry \u003d 2100 kgf / cm2
Determine whether the cross section of this rack is enough
1050/(0,52*5,88)=343.47< 2100, т.е. достаточно.

09-10-2014: Dr. Lom.

For pipe racks, it is indeed enough, but there is no for two-ranking beam, since the required moment of resistance is greater than the moment of pipe resistance. So it is better to leave a three-gun beam.

20-10-2014: Sergey

Tell me, dear doctor scrap, and for what technique you need to calculate the walls of the frame house? And do the right to the life of the design of the walls of the walls on the example of https://yadi.sk/i/obgwmseac9prm, the fact is that I need a wall thick for at least 18cm, and from that lumber, which can be bought from us I can do Racks at best width 13 or 15 cm. In the first embodiment, the width of the racks can be different from the same, say 8 + 8 + 2 (stated), before, for example 10 + 6 + 2. In the second, variation 13 + 13 or 15 + 15 with the allen. Step racks in both cases no more than 60cm. Thank you.

21-10-2014: Dr. Lom.

The design of the wall of the frame house depends on the calculated loads and may well be the same as on the figure you specified.
In the calculations of the racks, there is nothing complicated, see article "An example of calculating a wooden rack, compression ducts".

30-10-2014: Sergey

Dear, Doctor Scrap! Conducted calculations of racks based on "An example of calculating a wooden rack, a compression duct", there were even more questions. https://yadi.sk/i/ttgq6ourcpev8, https://yadi.sk/i/cx4er8kjcpfe9, https://yadi.sk/i/fx2bi7j1cpfhq, as seen in the first two cases, limit flexibility values \u200b\u200bexceed the valid values. Although I revised the mass of projects of frame houses and mainly the thickness of the racks there is 30-35 mm. But the whole design is then trimmed by plywood, OSB or boards and it turns out a hard box. Maybe proceeding from this, you can neglect flexibility? The next question is. If I collect racks in the http, as in the figure https://yadi.sk/i/7z7-21x5cpgmj, then what width to take B1 or B2? Or divide load? I assume the following design https://yadi.sk/i/q1bh0kzzcpgeu. How to calculate the rack if it passes through two floors?

30-10-2014: Dr. Lom.

Since your racks will be shifted by sheet material, then you need to consider not separately taken bars - racks, but the whole structure as a whole. In other words, you need to define all the necessary parameters for the composite section (for the 1st wall meter), as is done, you can see in the article "Calculation of the strength of the ceiling profile for drywall".
Even if the rack will pass through 10 floors, then the calculated length will be equal to the height of one floor if the overlaps prevent the horizontal movement of the racks (and so it usually happens).

05-11-2014: Sergey

Dear Doctor Scrap!
Taking over with formulas: Definitions of the situation of the severity
YC \u003d SZ / F \u003d (F1Y1 + 2F2Y2 + 2F3Y3) / (F1 + 2F2 + 2F3) \u003d (0.3x0.025 + 2x0.13x1.35 + 2x0.03x2.675) /0.69 \u003d (0.0075 + 0.351 + 0.1675) /0.69 \u003d 0.7623 cm.
And the moment of inertia
Iz \u003d? (IZ + Y2F) \u003d 6x0.053 / 12 + 6x0.05x (0.7623 - 0.025) 2 + 2 (0.05x2.63 / 12) + 2 (0.05x2.6) (1.3 - 0.7623) 2 + 2 (0.6x0.053 / 12) + 2 (0.6x0.05) (2.7 - 0.7623 - 0.025) 2 \u003d 0.0000625 + 0.16308 + 0.14646 + 0.07517 + 0.000012 + 0.2195 \u003d 0.6043 cm4.
It was confused with the values \u200b\u200bof U1, U2, and y3. If with u1 is more - it's clear, then with U2 and U3 confused. In the first case, U2 \u003d 1.35, y3 \u003d 2.675, then in the second 1.3 and 2.7, respectively. I sketched the drawings https://yadi.sk/i/m0qksgdpcvaqn and it seems to me that it should be more correct to be values \u200b\u200bU2 \u003d 1.347 and y3 \u003d 2.65. Or did I not understand something?
And if 1 Penate meter of the wall will look like https://yadi.sk/i/hxc0urrocvarb, how is it here to determine the provisions of the center of severity? Or you need to take this meter so that all the racks are symmetrically?

05-11-2014: Dr. Lom.

1. Since the center of gravity of the given section is not known to us, then the calculation is made with respect to the axes passing through the extreme lower (axis y) and the extreme left (axis z) of the cross-sectional point. Accordingly, U2 \u003d 1.35, and y3 \u003d 2.675 (however, the figure you specified does not correctly displays the position of the centers of the severity of simple geometric figures).
2. Even if you have an asymmetric section, the calculation algorithms do not change. The determination of the center of gravity of the given section is performed in exactly also (of course, with the elimination of equal estimated resistance of bars and sheet material).

06-11-2014: Sergey

Dear Doctor Scrap! I apologize for annoying, but I want to figure it out in this matter, and I did not study the conversion. Now https://yadi.sk/i/poh_ijyzcx4lt, I hopefully put the center and distances. In this design, should I consider the sections of all (1,2,3,4,5) elements? And the elements of 1 and3 should be considered as one-piece or if somewhere comes across the joint, then how are two different elements?
And also, doctor scrap, you need a purely practical advice. I get a big span, almost 6 meters, I do not want to put the columns. We need overlapping beams (inter-storey) with a height of more than 20 cm, and we are unreal if we find such a board, if you can order from somewhere, it will be golden. If I collect them so https://yadi.sk/i/1dcedvrkcx4wy, then you will need to be considered as a wall?

06-11-2014: Dr. Lom.

Yes, now you all put it all and you really need to first determine the area of \u200b\u200bcross sections of all 5 items. However, elements 1 and 3, 2 and 5 have the same area (judging by the figure), besides the distance from the center of gravity to the axis of elements 2 and 5 the same, which reduces the amount of mathematical actions. In addition, you can still simplify the calculations if you do not take into account the presence of an element 4. This element has a relatively small area and if it is not taken into account, then the result you received will give a small margin for strength, which will never hurt, but the cross section will then be Symmetric and center of gravity will then be in the middle of the height of the section and this will simplify the determination of the moment of inertia of the section.
Even if in the elements 1 and 3 there will be a joint somewhere, then it does not affect the value of the moment of inertia with respect to the axis under consideration, so these items can be viewed as one-piece, of course, provided that the slot on the junction will be small, however, it may be useful By strength.
Yes, the moment of inertia and the moment of resistance for transverse sections of the beam is also determined as for the cross section of the wall. For information, you can look in the article "Moments of inertia of cross-section."

07-11-2014: Sergey

Dear Doctor Scrap! It reached the calculation of the bending moment https://yadi.sk/i/xjifmrkycyx86 and quarreling again. Estimated wood resistance 130kg / cm2, plywood RF \u003d (180 + 110) / 2 \u003d 145kg / cm2. And what would make them shared, you need to take a medium or somehow different? And formula, I hope correctly wrote?

07-11-2014: Dr. Lom.

In order not to mess with the definition of the characteristics of the given section, simply make a calculation by the smallest calculated resistance. This will again give a small margin for strength, as the difference between the calculated resistance is not big.
And yet, since you have a symmetric section, the center of severity will be on the same axis as the centers of gravity of bars. Those. Us \u003d U2 \u003d 8.4 cm. And the error came from you due to the fact that you incorrectly determined the values \u200b\u200bof u1 and y3 (0.9 / 2 \u003d 0.45 and not 0.045). In addition, in determining the moment of resistance, the value of the moment of inertia should be divided into US (U2).

07-11-2014: Sergey

Corrected, it turned out so https://yadi.sk/i/hhfr-js0czrtc. If I understand this calculation correctly, the meter of such a wall will keep one and a half tons boldly, i.e. Inter-storey overlap, the walls of the second floor, the attic overlap and the roof can be put?

07-11-2014: Dr. Lom.

Maybe it will endure, but only it is necessary to check this. And I do not deal with the calculations, I can only tell the theory of something.

08-11-2014: Sergey

And what did I think this is not a calculation? Or probably need to count something else? Please tell me.

08-11-2014: Dr. Lom.

The calculation of course, and not quite the one. You seem to be going to check the frame wall on stability (i.e., the construction on which longitudinal loads will be mainly acting), and not the beam on the action arising from the action of the transverse forces. Return to the article "An example of calculating a wooden rack, compression ducts". And if part of the load to your walls will be applied with an eccentricity, for example, from the beam of overlapping, then further consider the moment that occurs, this example is in the article "Calculation of metal columns".

02-07-2015: Alexei

Good afternoon, doctor scrap! I decided to calculate the floor plate of the garage with the basement under two cars. The walls of the basement T \u003d 400 mm monolithic, 7x7 m plate with a thickness of 200 mm. Based on your scheme, it suggested that the most unfavorable position of the machines will be if they stand on each other (which can not be, but I don't know how to calculate). Given that the weight of the car 2000kg, then put the wheel on the floor from two cars will be 1000 kg:
M (auto) \u003d (250 + 1000 * 50/700) * 500 \u003d 160714,3kgs * cm
Temporary load: Q (B) \u003d 400 kg / sq. M.
Floor load: Q (floor) \u003d 100 kg / sq. M.
Load from overlapping: q (plate) \u003d 500 kg / sq. M.
Q (total) \u003d 400 + 100 + 500 \u003d 1000 and multiply on the coef. Reliability 1.2 \u003d 1200 kg / sq. M.
Ma \u003d Q (total) * L * L / 16 \u003d 1200 * 49/16 \u003d 3675kg / m
M \u003d (MA + MB) / 2 \u003d (3675 * 1,4142 + 3675) / 2 \u003d 4436.1 kgm * m
M (max) \u003d m + m (auto) \u003d 443610 + 1607144,3 \u003d 604324,3kgs * cm
We select fittings:
Ho1 \u003d 18cm
HO2 \u003d 16cm
Concrete B25 RB \u003d 147kgs / cm2
AO1 \u003d 604324.3 / (100 * 18 * 18 * 147) \u003d 0.127; n (o1) \u003d 0.93; E (o1) \u003d 0.14;
AO2 \u003d 604324.3 / (100 * 16 * 16 * 147) \u003d 0.16; n (o1) \u003d 0.91; E (o1) \u003d 0.18;
FO1 \u003d 6043,243 / (093 * 0.18 * 36000000) \u003d 10 sq. Cm;
FO2 \u003d 6043,243 / (091 * 0.16 * 36000000) \u003d 11.53 sq.m.
On the table we accept the reinforcement 16 sh. \u003d 150 * 150 f \u003d 12.06kv.cm.
I want to lay the top and bottom mesh with reinforcement 16 sh. \u003d 150 * 150. Tell me how correctly I picked up the grid, do I think right? How to calculate the deflection? What and how to count more?

03-07-2015: Dr. Lom.

In principle, you worked well and almost all considered, but there are several comments:
1. Your situation is somewhat different from the article described in the article. The most unfavorable option will be the option when 2 cars will stand near and, accordingly, 4 conditionally focused loads from the wheels will act on the slab. Therefore, it makes sense to simplify the calculations of these focused loads to the equivalent uniformly distributed (all equal to the support reaction and, accordingly, the bending moment from cars you were determined incorrectly). Check out the article "Determinating a focused load to evenly distributed."
2. With this diameter of the reinforcement, the protective layer is not sufficient, i.e. It should be accepted and at least 2.5 cm and respectively, HO1 \u003d 17.5 cm.
For the upper mesh, it is possible to use the reinforcement of a smaller diameter, amplifying it with additional rods along the contour of 1-1.5 m long. If you will lay the reinforcement and in the upper and in the bottom zone of the section, you will need transverse fittings (however, it will still be needed. As the height of the plate is more than 15 cm). How to pick it up, look in the article "Constructive Requirements for Reinforcement Balls and Plates of Overlapping."
Regarding the deflection, there are articles "Determination of the L / B beam deflection", but you can also use the coefficient, see the article "Tables for calculating plates, hinged-opened by contour."

07-07-2015: Alexei

Good evening, Dr. Scrap! Thanks for the comments! Continued to consider, given your comments:
According to the article "Developing a focused load to uniformly distributed":
The article indicates two options: a) M (auto (a) \u003d 1,2 * 4 * Q * L ^ 2/8 * L \u003d 1.2 * 4 * 500 * 7 * 7/7 * 8 \u003d 2100kgs * m
M \u003d 4436.1 kgm * m
M (max (a) \u003d m + m (auto) \u003d 4436,1 + 2100 \u003d 6536,1kgs * m
We select fittings:
Ho1 \u003d 17.5cm
HO2 \u003d 15.5SM
Concrete B25 RB \u003d 147kgs / cm2
AO1 \u003d 653610 / (100 * 17.5 * 17.5 * 147) \u003d 0.1452; n (o1) \u003d 0.92; E (o1) \u003d 0.16;
AO2 \u003d 653610 / (100 * 15.5 * 15.5 * 147) \u003d 0.16; n (o1) \u003d 0.895; E (o1) \u003d 0.21;
FO1 \u003d 6536.10 / (0.92 * 0.175 * 36000000) \u003d 11.3 sq. Cm;
FO2 \u003d 6536.10 / (0.895 * 0.155 * 36000000) \u003d 13.1 sq. Cm
On the table we take the reinforcement 18 w. \u003d 150 * 150 f \u003d 14.07kv.cm.
Further on the article "Tables for calculating plates, hinged-opened by contour":

F \u003d -K * Q * L ^ 4 / (E * H ^ 3)
Q \u003d 1.2 * 4 * Q / 8 * L \u003d 1.2 * 4 * 500/8 * 7 \u003d 43kg / m
f \u003d 0.0443 * 43 * 7 ^ 4/30 * 10 ^ -3 * 102000 * 0.2 ^ 3 \u003d 187 cm
F \u003d 187cm a lot, I decided to calculate on the article "Determination of the deflection of w / b beams":
f \u003d k * 5 * q * l ^ 4/384 * e * i
k \u003d 0.86
Q \u003d Q (auto) + Q (common.) \u003d 43 + 1200 \u003d 1243 kg * m
W \u003d Q * L / 8 * Rb \u003d 12.43 * 700 ^ 2/8 * 147 \u003d 5180 cm3
y2 \u003d (3 * w / 2 * b) ^ 0.5 \u003d (3 * 5180/2 * 100) ^ 0.5 \u003d 8.82
Y ^ 3 \u003d 3 * As * (HO-Y) ^ 2 * ES / B * EB
y \u003d 9,59 cm
y (p) \u003d y- (y2-y) \u003d 9,59- (8,82-9,59) \u003d 10.36cm
I \u003d 2 * b * y (p) ^ 3/3 \u003d 2 * 100 * 10,36 ^ 3/3 \u003d 74129 cm4
f \u003d 0.86 * 5 * 12,43 * 700 ^ 4/384 * 300000 * 74129 \u003d 1.5 cm

Now I considered for option b) m (auto (b) \u003d Q * L / 2 \u003d 500 * 7/2 \u003d 1750kgs * m
M \u003d 4436.1 kgm * m
M (max (b) \u003d m + m (auto) \u003d 4436,1 + 1750 \u003d 6186,1kgs * m
We select fittings:
Ho1 \u003d 17.5cm
HO2 \u003d 15.5SM
Concrete B25 RB \u003d 147kgs / cm2
AO1 \u003d 618610 / (100 * 17.5 * 17.5 * 147) \u003d 0.138; n (o1) \u003d 0.925; E (o1) \u003d 0.15;
AO2 \u003d 618610 / (100 * 15.5 * 15.5 * 147) \u003d 0.175; n (o1) \u003d 0.9; E (o1) \u003d 0.2;
FO1 \u003d 6186.1 / (0.925 * 0.175 * 36000000) \u003d 10.6 sq. Mc.;
FO2 \u003d 6186.1 / (0.9 * 0.155 * 36000000) \u003d 12.3 sq.m.
On the table we accept the reinforcement 18 sh. \u003d 200 * 200 f \u003d 12.7kv.cm.
Further on the article "Tables for calculating plates, hinged-opened by contour":
Calculation of the deflection produced for the option "A"
F \u003d -K * Q * L ^ 4 / (E * H ^ 3)
Q \u003d 4 * Q / L \u003d 4 * 500/7 \u003d 286kg / m
F \u003d 0.0443 * 286 * 7 ^ 4/30 * 10 ^ -3 * 102000 * 0.2 ^ 3 \u003d 1242.7 cm
F \u003d 1242.7 cm very much, I decided to calculate on the article "Determination of the deflection of w / b beams":
f \u003d k * 5 * q * l ^ 4/384 * e * i
k \u003d 0.86
Q \u003d Q (Auto) + Q (commonly.) \u003d 286 + 1200 \u003d 1486 kg * m
W \u003d Q * L / 8 * RB \u003d 14.86 * 700 ^ 2/8 * 147 \u003d 6191.7 cm3
y2 \u003d (3 * w / 2 * b) ^ 0.5 \u003d (3 * 6191.7 / 2 * 100) ^ 0.5 \u003d 9.64
Y ^ 3 \u003d 3 * As * (HO-Y) ^ 2 * ES / B * EB
y \u003d 9.4 cm
y (p) \u003d y- (y2-y) \u003d 9.4- (9,64-9.4) \u003d 9.16cm
I \u003d 2 * b * y (p) ^ 3/3 \u003d 2 * 100 * 9,16 ^ 3/3 \u003d 51238,4 cm4
f \u003d 0.86 * 5 * 14,86 * 700 ^ 4/384 * 300000 * 51238,4 \u003d 2.6 cm
Tell me rightly considered and there is no mistakes in the translation of units. ?

08-07-2015: Dr. Lom.

With the selection of the secting of the reinforcement, you seem to be all right. But this is so, on the eye, I have already said that I do not check the accuracy of calculations. But when determining the deflection, especially using the coefficient, you made several errors (however, this calculation of 2 groups of limit states and nothing terrible in it). So when determining the deflection, firstly followed the total load value. At the same time, the value of the equivalent distributed load from cars was not particularly determined, it would be more, somewhere 350-400 kg / m, and not 43 for 1 option (in the second version, you kind of determined the load from cars more accurately). Next, the table value of the modulus of elasticity for concrete 30x10 ^ 8 kg / m ^ 2, if you think in meters, or 300,000 kg / cm ^ 2 when calculating centimeters (with this calculation, you are not mistaken). And what is the number - 102000 - I did not understand at all. In general, the whole calculation looks less believable.

29-10-2015: Albert.

Hello! Wonderful site. According to reactions, I would like to clarify. Your "In Embodiment B, the reaction of the left support 250 + 500x350 / 400 \u003d 687.5 kg." The result is correct, however, in the numerator number 250. This is what? Reaction of the left support: (500 * 350 + 500 * 200) / 400 \u003d 687.5. I'm wrong?

29-10-2015: Dr. Lom.

That's right, I simply did not remember that with a concentrated load applied in the midst of the flight, the reaction is equal to each other and make up half of the applied focused load (it is like a ride of the ride, but maybe this item should not be lazy and painted in more detail that, However, I'm doing now). Thus, the support reaction from one wheel is 500/2 \u003d 250 kg and only the reaction from the second wheel should be defined, and then folded the data obtained.
However, as I said, your recording equation is more correct, although it requires more mathematical actions.

It would be wrong to leave the clay or soil floor in the garage, since the earth ground is not particularly durable and as a result of constant loads and exposure to the time will see and deform. In addition, the soil easily absorbs various toxic substances and gasoline, so it will not get rid of the unpleasant smell in boxing. Another thing is a wooden floor in the garage, this wear-resistant, attractive and durable coating will serve you for many years. Unlike concrete floor, the wood coating is better preserved heat indoors, not dust and looks more attractive.

Requirements for garage coverage

Before making the wooden floor in the garage with your own hands, you need to explore the requirements for this coating:

Tree surface It should be resistant to mechanical damage, so it is better to choose solid wood boards.
The flooring should be well to resist the effects of aggressive chemistry. For this, the wooden floor is treated with special impregnations, and also covered with protective compositions.
The boardwalk must be fireproof. To protect against fire, wood must be soaked with antipirens.
The surface should be moisture resistant. To this end, the board can be covered with oil or varnish, but it should be remembered that when moving on the floor, your legs should not slide.

Important! When choosing a material and method of flooring device, it is important to give preference to inexpensive and reliable structures, take into account the simplicity of installation and duration of operation.

How to choose wood for the floor in the garage?

Before making the floor in the garage from the board, you need to choose the wood suitable for this room. Laying chalkboard from nut and mahogany in conditions of increased loads, humidity and effects of aggressive substances inexpex.

Prefer coniferous rocks, as they have high wear resistance and durability. It is best to make the floor in the garage of oak. This breed due to high strength and hardness will serve not one decade.

When choosing wood, consider the following rules:

to avoid deformation of the coating for the floor of the floor in the garage, apply only well-leaked wood (Peresked or raw boards are not suitable);
for a framework of a frame of a lag, choose only entire bars without cracks and other defects;
after calculating the amount of wood, always take a 15 percent stock.

What to treat the tree before laying?

To protect the wooden floor in the garage to protect against rotary processes and damage insects, all elements of wood are treated with antiseptics. Prix \u200b\u200bproducts need to be styled. The primer is applied in several layers. All products are well dried after applying impregnation.

Sometimes antiseptics are applied only with the wrong side of the board. For these purposes, sodium fluoride and borate-based mixtures are suitable. White powder without smell is bred in water. After cooking and application, the composition does not change the color of the material, does not reduce its strength and protects metal structural elements from corrosion.

Tip! To protect against moisture, the bars are covered with water-repellent, deep penetrating impregnation on the basis of solvents. They create a protective thick film. Oil analogs are allowed to apply for processing only absolutely dry wood.

The floor in the garage from the boards must be protected from fire. For this, wood is treated with antipirens. These are special substances that increase the fire resistance of the material. Antipirens are applied to lags and boards to their laying. It is better to use compounds based on copper hydroxide.

Step-by-step Montaja technology

If you make the wooden floor in the garage with your own hands, then the optimal version is the device of a wooden design by lags. So the load will be evenly distributed over the entire flooring and transmitted to the Earth. In addition, if there is a heater between lags, the room can be additionally protected from the cold. Designs on lags allow you to hide base defects. In space under the floor, various engineering communications are laid.

Note! Lagam floors are not suitable for low garages, since such a design lifts the floor level by 6-10 cm. In this case, the floor of the tree in the garage is made along a concrete base.

Laying of wooden floor on a concrete basis

The concrete base does not need special preparation, so work on laying the board is beginning at any time.
At the same time adhere to the following recommendations:

for laying use boards with humidity no more than 10%;
pre-arrange a frame of 50x50 millimeters bars, which are installed in 400-500 mm;
the first lighthouse bars are stacked with a step of 2 m;
for fixing to the concrete base, dowels are used, which are fixed with increments of 500 mm;
then stacked intermediate bars and also fasten them to the base of the dowels;
next, begin to install the flooring;
the boards are laid out perpendicular to the frames of the frame and attach to them with nails or self-tapping screws.

If the concrete base is flat enough and does not have serious defects, then the flooring is performed without the use of a frame from bars. Flooded boards are suitable for styling. Before use, they are impregnated with oil to protect against moisture and paint. After drying, they begin to install the female floor. The boards are laid over the entire length of the room and attach to concrete again with nails or self-tapping screws.

Laying of wooden floor on the ground

Several more difficult to install the wooden floor on the ground base. At first, the base is carefully prepared, and after the floor laying in several stages:

The surface of the soil in the garage is aligned with a chipset or robber.
Next, perform sand-gravel backfill. At the same time, a layer of sand is poured at a height of 15 cm first, then a layer of clayjit or gravel is the same height. If desired, the thickness of the gravel layer can be reduced to 10 centimeters.
Then the sandy-gravel pillow is spilled with water and is good tamper. It is best for this to use an electric traam (manual roller, vibrating plastic or manual traam).
We put the waterproofing material over the entire surface and we start it on the walls to a height of 10 cm. The joints of the material glue with mastic or tape.
We proceed with the installation of the lag. For this, the bars section 100x100 mm are suitable. First we set the bar around the perimeter of the room. It will distribute the load from the car and weight of all the floor. At the corners of the sawn timber fasten with metal corners among themselves. With the level of level, check the horizontal position of the bars. If required, under the elements are putting cutting boards or plywood.
Next to the entrance to the garage also set lags with a cross section of 100x100 mm. Step between them is no more than half a meter. To fix them to the Low Armage Bruster around the perimeter of the room, we use metal M-shaped products or screws.
In the obtained empties between the lags, we embarrass the grainsite or sand for insulation of the floor of the room.
After that, we proceed to laying the flooring. They are located across the lag and attach them with the help of self-tapping screws in two points. In order for the floorboards tightly to lags, the holes under fastening elements are drilled in them. For this, the drill is used, the diameter of which is 1 mm less than the diameter of the self-press.

Tip! Before laying on the edges of each board with a stapler fasten the rubberoid strips for better insulation of the room and decrease the slots.

When the wooden floor is appliance, brick or concrete column columns can be used as a support. This method is suitable for garages in which the soil floor is significantly lower than the ground level. Due to the device of the columns, it is cooled without sand-gravel layers and waterproofing. Between the rows of columns make a distance equal to 800 mm, and the step of the columns in one row is 300 mm.

Attention! In order for the floor in the garage to be bombing under the weight of the car, for its device take the board with a thickness of at least 5-6 cm. The floorboards necessarily cover the oil and color.

How to cover the surface of the tree after laying?

After assembling the design, the question arises, how to cover the wooden floor in the garage? It is not worth leaving the boards without the finish protective coating, because so the surface will not be protected from mechanical exposure, absorb fuel and lubricants and moisture.

The following compositions are used to protect the floor:

Covering half a varnish You will get a durable, transparent and moisture-resistant coating. Wear-resistant varnishes on a polyurethane basis are ideal for the garage. Such coatings are protected from premature rotting of boards, do not crack, withstand temperature and humidity drops, do not lose their initial qualities during operation.
Floor paint paint Increases the aesthetic attractiveness of the coating and protects it from the short-term exposure of moisture. For boxing, paints are suitable based on an organic solvent.

Some boxing owners do not pay much attention to floor covering in the garage, preferring to leave the rammed soil or clay. This approach will eliminate the hassle associated with the arrangement of the coating and its repair. However, the earth floor is not particularly durable, therefore, under the influence of constant loads, it is easily deformed. He also absorbs gasoline and other substances whose smell is very difficult to bring out of the box.

The most optimal option for the garage is the floor of concrete or wood. Such coatings are characterized by high mechanical strength, wear resistance and an attractive appearance. Let us dwell in more detail on creating wooden floors, as they look more interesting and have the ability to maintain heat, unlike a concrete surface, which almost always remains cold.

Before proceeding directly to the arrangement of the floor covering, it is necessary to choose the right wood to create it. Definitely it is worth abandoning the idea to use in boxing red wood and nut. A good option is coniferous rocks that are characterized by excellent strength and resistance to wear. But it is best to stop your own choice on the oak, because the oak floor will last much longer the coatings from another timber.

When choosing a material, you must adhere to several simple rules.

In front of the arrangement of the floor, wood must be treated with antipirens - means to increase the fire resistance of the material, as well as substances that prevent the occurrence of concrete processes.

Antipirens increase wood stability to ignition

Wood floor mounting in the garage

As a rule, the car boxes are installed outdoor structures on lags, which allow you to evenly distribute the load throughout the floor. With the help of floors on the lags, some base defects can be hidden, as well as communication systems, such as an electrical cable. However, this design "raises" the floor by 6-10 cm, so it is not quite suitable for very low garages. Wood floor installation technology in the garage depends on the available base, which can be concrete or soil.

Installation of wooden floor on concrete base

The base of concrete does not need to be prepared, so you can immediately begin directly to the installation of the wooden floor. Experts give several basic recommendations on this process:

you can only lay material whose humidity is not more than 10%;
installation of lag is performed with a certain step distance, which often varies from 40 to 50 cm;
the first on the concrete base are mounted lighthouse lags, the step between which is approximately 2 m;
lag fixation is carried out with the help of dowels, the distance between them is 50 cm;
intermediate lags are stacked by the same scheme as lighthouses. Only after their installation proceed to laying flooring.
outdoor boards are placed perpendicular to lagas and recorded by self-draws or nails.

In fact, in the presence of a concrete base, it is not necessary to stop your choice on the lag design. If the draft floor does not differ in serious drops in height and does not have large-scale defects, then thick floor boards are completely suitable for the coating arrangement. Before starting the installation, the floats are treated with oil and color, then laid on a pure concrete base. The laying is carried out along the entire length of the garage, the boards of self-draws or nails are fixed.

With the installation of wooden floor on a concrete base in the garage, even a person without training, the main thing is to clearly follow the recommendations of specialists and adhere to technology.

Installation of wooden floor on the ground base

If the base in the garage is not concrete, but is a conventional soil, the installation of a wooden floor becomes a somewhat more complex process for which patience and a certain skill will be needed. In this case, the preparation of the foundation is necessary, and the laying itself will be carried out in several stages:

The primer surface is spilled, for this you can use a rake, as well as a conventional garden chip.
A sandy-gravel pillow is created: first goes 3-4 cm layer of sand, then the gravel or claymzite layer of the same thickness. In principle, the second layer may be somewhat thicker, since it is created from materials, the fraction of which is at times exceeds the dimensions of the sand grains.
The laid sandy-gravel pillow is pillowed with water, and then it is good tamper. You can do it with your hands and legs, although it will be much more efficient to use a specialized device - electric traam (or vibrating plates, manual roller, manual traam).
Lagges are mounted, which are wooden bars holding all the outdoor design. Since the base does not differ in strength and is easily deformed, the lags are installed on pre-laid smooth boards, and they must be thick enough to not be fed during operation.
The grounds for laying the lag on the soil (pits under the columns, if necessary, dig up to the backfill of rubble and sand)

All used wood should be impregnated with special compositions to give the material of the best moisture resistance, because the fact that it is not distinguished by the resistance to moisture and is subject to putrid processes - it's no secret. This recommendation is better not to neglect!

As a support for the future floor, it is not at all necessary to use only boards, they can be replaced with brick or concrete pillars - they will greatly cope with the task. Such supports are mounted by rows, the distance between which is 80 cm. The step between the columns themselves should be 30 cm.

Video - Wooden floor in the garage. Lags for soil

Among other subtleties of the wall flooring on the ground base in the garage, the following points can be distinguished:

lags are desirable to have perpendicular to the movement of the vehicle, and the floor boards themselves - in the direction of movement. Compliance with this rule will help make the design more durable, and the floor will become much stronger;
outdoor boards must have the same thickness - approximately 50-60 cm. You should not take more subtle fees, otherwise the floor will simply be fed under the weight of the car and quickly fails;
before mounting the board, it is necessary to dry and coat with antifungal agents. Their opposite side, which will touch with a sandy-gravel pillow, must be treated with waterproofing compositions.

After the arrangement of a wooden floor covering, many garage owners leave it in primea, which is very in vain, because wood is a material that needs careful attitude. The floor should be covered with oil and paint, because it is possible to protect the flooring from oil and gasoline spots that are practically impossible to output.

Video - Wooden floor in the garage. Installation, part 1

Video - Wooden floor in the garage. Installation, part 2

Video - Wooden floor in the garage. Installation, part 3

Video - Wooden floor in the garage. Installation, part 4

Video - Wooden floor in the garage. Installation, part 5

Chipboard and plywood floor in the garage

There is another way to create a wooden floor in the garage, which implies the use of plywood or chipboard. These materials will serve as the basis for the leveling layer, the thicker it turns out, the lags will be laid with a big step. Having completed with the installation of beacons, you can move to the installation of the lag, fixing them on the base with glue or self-drawing.

In places of fixation placed plywood pieces treated with glue. On top of the resulting mesh, the sheet material is stacked, which aligns the floor. It is attached to the lags by self-drawing, on 1 sheet goes about 9 pieces. The moisture protective film is placed on the leveling layer, and then the insulation slabs. All this is covered with floorboards. Thus, the floor in the garage becomes perfectly even and very durable.

Deciding on the creation of a wooden floor covering in its car box is not a barrier to arrange the observation pit. It is possible to organize it in several stages:

The required depth of the required depth is created, the bottom of which is laid out with a platerled brick, placed perpendicular to wall surfaces.
The walls of the observation pit are facing the brick, which is located in the edge.
The space between the brick masonry and the soil is filled with the concrete mixture, it is done as the height of the walls is grown.
Brickwork is carried out until it reaches the level of lag. Thus, the fees will partially lie on the masonry. The remaining space is mounted frame, which places closing the pit.
Metal corner laid on the walls of the observation pit

To equip a viewing pit in a garage with a wooden floor is simple enough, you only need to make a little effort and follow the recommendations received.

Video - observation pit in a garage with a floor of a tree

Wooden features in the garage

The wooden floor in the garage is an environmentally friendly coating, which, with the right installation and care, will delight the owner of the boxing of the box not one year. However, the decision to create sex from wood in the garage cannot be called definitely correct, in any case, so consider some car enthusiasts, which are categorically against the use of this material. Take the right solution will help analyze the advantages and minuses of this coverage.

The advantages of choosing wood for flooring in the garage include the following factors:

wood is distinguished by a long service life, especially after impregnation with protective equipment. Wooden floors can serve about 10 years, not deformed and not destroying;
if part of the coating was damaged, then it can be relatively easy to replace without dismantling the floor;
the wood is hygroscopic, that is, absorbs moisture out of the air, which helps to maintain the optimal indicators of humidity in the garage, and this favorably affects the state of the vehicle;
wooden floor, unlike concrete coating, well keeps warm, so work on it is safer to health. Wood as an outdoor coating often choose people who independently repair their cars;
in terms of strength, the thick floorboard is not inferior to the screed of concrete, so it can be used even in boxes for small trucks;
on the concrete floor, dust is formed, with a wooden coating such a problem will not arise.

There are wooden floors in the garage and their shortcomings to which the ability to absorb smells, exposure to putrid processes, as well as low refractory. However, all these disadvantages can be easily leveled by using special impregnations that make the operating indicators of wood much better.

Wooden floor after staining

Summing up, it should be noted that the wooden floor covering in the garage is a rather controversial solution with its advantages and disadvantages. Give him preference or not - depends on the needs of the owner of the car. If he has to work often in boxing, it is better to stop his choice on wood, rather than risking health, lying on a cold concrete tie. And to preserve the appearance of the coating, you can use special rubber lines or rubberoid stripes by which the car will travel and drive.

Good day. Can you suggest which weight withstands the edged board depending on the thickness of 1 m2 of the collection board from the board or the temporal meter of the board with a load from above? Are there any lower on this information?

Alexey, Perm.

Hi, Alexey from Perm!

For example, no scientific luminaries can explain why during draining the water through the hole at the bottom of the bath is formed a funnel? How many copies around this effect were broken, and there is no reliable explanation.

I am not so strong in theoretical physico-mathematical calculations to give the correct answer to the mountain.

In my opinion, the magnitude of the load per square meter of the shield of the edged board can reach several tens of tons.

If you consider the physical meaning of this problem, then with incomparably different densities of the base on which the shield from a wooden board is lying (for example, under the shield - the perfectly smooth surface of concrete monolith or a steel sheet with a thickness of 20-30 millimeters), evenly distributed to each square millimeter loading shield (Suppose that laid strictly vertically on each other with cast concrete cubes with the size of the edge of 1 meter), the weight can reach from several tons and to twenty-thirty tons.

And the thickness of the board here plays an indirect role. We are talking about constant, and not about dynamic load. At the last - the destructive loads can be less than several orders of magnitude.

That is, by applying enough macimal value to the shield load, we, when it reaches it, for example, thirty with excess tons, we can observe the effect of crumpled wood. And if after this load will be removed, the wood will be "flattened".

I base on visual effects when it was converted to see wooden beams, mounted (stamped) into the walls and towers of medieval fortresses and monasteries. Above these beams there was a stone laying in several tens of meters high, therefore the weight of the beams approximately corresponded to dozens of tons.

Of course, the wood breed and the degree of moisture of wood play an important role. It is one thing if the wood of the Grab, ash, maple and completely different - aspen or needles.

The wood is completely different and at different types of loads, and they can be directed both along the fibers and across.

As for the console location of a wooden shield or a cutting board, there are already completely different principles. That is, if you have a cutting board in the thickness of the wall so that approximately the meter is inside the wall and it protrudes from the wall, and you apply an ever-increasing load by the end of the protruding board. When the limit load is reached, the boards will occur, as a rule, at the end of the wall surface.

Elementary theoretical mechanics plus conversion. There is a pinched beam, the shoulder, the point of the application of force, the moment of force is formed. The more shoulder, the smaller the power can be applied to avoid a break.

And the cross section of the edged board is crucial. The more, the stronger the beam. If the board is installed on the plastics, then it is withstanding a smaller destructive load. If the board is installed on the edge, the destructive load can achieve significantly large parameters. Therefore, in the house structures, the edged boards are almost always installed on the edge (gender lags, beams, riglels, rafters).

In addition, it is important not only that, but also the quality of the wood, the presence of bitch, detachals, cracks, bumps and other vices. It is undesirable to use the central parts of the barrel, the middle and upper parts. Superframe. It is preferable to a commute part, wood blank during the minimum saxation period (exception - aspen), some other factors.

Therefore, taking into account all the above, I can not give you thorough calculations at what maximum values \u200b\u200bof voltages in the wood comes the tensile strength of it.

If you are still interested in this topic, then you can look more in the Internet in the sections of the wood strength during static loads and in relation to your option. SNiP II-25-80 is what interests you. / Although I will immediately say that it will not be easy to understand the materials.

Personally, we in our team adhere to more intuition, and not use reference data. And so, according to the working and peasant, the more powerful the cross section of the board, the more it is withstanding the load.

He answered as he could, who would explain more accessible, I will be grateful.

Ask a question Seeds (author's author)

Our site is regularly replenished with interesting and unique materials and articles on lumber, building materials and works, the author's opinion and knowledge of the real joint with the experience of more than 15 years is given. There is a section - funny stories of shabashnikov. If you wish to receive information about it, subscribe to the newsletter of our site. It is guaranteed to the indescribing of your address to third parties.

Wooden floor in the garage is not the best coating. The tree can quickly collapse and absorb oils and other technical fluids. Wood is breathtaking and processed from excess moisture. Such gender is safe in fire ratio. It is possible to make the wooden floor in the garage with your own hands, but it follows this coating as temporary. Installation does not require large investments, it will last 5-10 years.

Required tools

How to make a wooden floor in the garage? For its installation it is necessary to prepare materials and tools:

siping board;
a hammer;
nail holder;
stapler;
mounting;
screwdriver;
hacksaw;
nails or dowels and screws;
shlifmashin;
tool for measurements;
mounting thread;
olif;
oil paint;
antiseptic;
painting brush;
roller

How to make a wooden floor

The garage is a storage for the car. To withstand its weight, you must have a solid foundation. It can be organized in the following ways:

build a pillow from sand and gravel and pour it with concrete;
install brick columns on the ground.

The case with a concrete pillow is used often. On the finished base, the boards are stacked, the thickness of which is 25 mm and more. Well, if the boards have a thickness of about 50 mm. Then lags can be laid with a wider step. Lags are made from a bar 100x100 mm. All wooden details need to be well treated with antiseptics and dry. Work can be performed in the following order:

Located on concrete waterproofing.
Lags are installed.
Floor insulation is done.
Mounted boards.

The waterproofing layer is made of rubberoid, PVC films. You can apply new materials from membrane films. The canvases of the film or rubberoid are put on the shoulder, the joints are sampled with scotch with water-repellent properties.

Lagges are installed on a concrete base in approximately 40 cm increments. Equality of laying is controlled by the level. The lags are attached to the concrete of a dowel. Inside the frame laid the material of the insulation. It can be a foam, mineral wool, clay. From above, the insulation is closed with a layer of film.

Boards should be laid, without cracks. Halls are attached to lags by self-drawing. You can use nails. The boards should be placed along the car - so they will last longer. Instead of boards, the use of thick plywood is allowed.

In the absence of a concrete base, brick columns under lags are installed. For their manufacture, an ordinary red construction brick is taken. Size of columns - 25x25 cm. Height can be different. Soil under the columns is specifically prepared. This is done like this:

the surface is aligned;
watering water;
installed columns.

Clean river sand is poured on the aligned surface. The layer thickness is 4 cm. A layer of gravel or clamzite is placed on top of it. 3 cm thick. Both layers are thoroughly poured with water and tram. Brick columns are put in rows in those places where the lag is planned. The distance between the supports is approximately 80 cm, the pitch of the series is 30 cm. On top of the columns, insulation of rubberoid and lags are stacked. Then you can warm the floor and put the boards. In the future, boards can be painted.

For the floor in the garage you need to choose the board not only in thickness. It is better to make the floor of wooden boards of coniferous breeds. It may be pine, spruce or larch. Oak is suitable from hardwood. But this pleasure is very expensive. All material should not have cracks and other defects. Nails are nailed to the board to a depth of 3 mm from the surface. The holes are embarrassed and painted.

The use of screws and self-tapping screws is a more reliable way, but also more laborious. For each fastener, you must drill the hole in the board and remove the chamfer from it. Between the walls and edges of the boards, it is necessary to leave the gap of about 1.5 cm. In the future, it will close the plinth.

You need this clearance to compensate for the temperature expansion of the flooring. To obtain a perfectly smooth surface, you can process the finished floor of grinding. On this wooden floor device in the garage can be finished.